A drum has 40kg of water. From this drum 4kg of water was taken out and replaced with milk. This task was repeated twice. How much water is now in the drum?

29.16

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30.16

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15.08

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14.58

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None of the above

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Solution

The correct option is A
29.16

Water in the drum $(A) = 40 k g$ .

Water taken out each time $(B) = 4 k g$

No. of times = 3

Remaining water in the drum = $A [1 - {(\frac{B}{A})}^{n}] k g$

$= 40 [1 - {(\frac{4}{40})}^{3}] k g$

$= 40 {(\frac{9}{10})}^{3} k g$

$= 40 (\frac{729}{1000})$

Remaining water in the drum = 29.16kg

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A drum has 40kg of water. From this drum 4kg of water was taken out and replaced with milk. This task was repeated twice. How much water is now in the drum?

The correct option is A 29.16 Water in the drum (A)=40kg. Water taken out each time (B)=4kg No. of times = 3 Remaining water in the drum = A[1−(BA)n]kg =40[1−(440)3]kg =40(910)3kg =40(7291000) Remaining water in the drum = 29.16kg