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Question

A drunk person moves such that after three consecutive steps forward he takes one step backwards. There is a ditch 10 m away from him when he starts moving in its direction. If his each step is 1 m long and he takes 1 sec to take each step, his average velocity till he falls in ditch is [step in which he falls should not be counted]

A
1017 m/s
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B
12 m/s
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C
1 m/s
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D
59 m/s
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Solution

The correct option is D 59 m/s

<v>=DisplacementtimeDisplacement=10 m
For every 2m forward, the time taken is 4 sec. This happens upto 8m. After 8 m, he takes two steps to fall into the ditch.
So time 4×4+2=18 sec
<v>=1018m/s=59m/s

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