Question

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:

• A. 21 s
• B. 29 s
• C. 31 s
• D. 37 s

Answer 1

The correct option is (B) 29 s

According to the question

The person moves 5 steps forward and 3 steps backward in 8 sec after that he is 2 m away from an initial position

We can write as

X = 5-3=2 m in 8 sec

After 24 sec he will be 6 m away from an initial position.

He moves further 5 m forward then he falls in a pit which is 11 m away from the initial position.

Total time T = 24 + 5 = 29 sec.

Hence option B is correct.