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Question

A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward,followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. Plot the x-t graph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start.

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Solution

time step distance
0 0 0
1 1 1
2 2 2
3 3 3
4 4 4
5 5 5
6 6 4
7 7 3
8 8 2
9 9 3
10 10 4
11 11 5
12 12 6
13 13 7
14 14 6
15 15 5
16 16 4
17 17 5
18 18 6
19 19 7
20 20 8
21 21 9
22 22 8
23 23 7
24 24 6
25 25 7
26 26 8
27 27 9
28 28 10
29 29 11
30 30 10
31 31 9
32 32 8
33 33 9
34 34 10
35 35 11
36 36 12
37 37 13

Lets call 1 cycle = going forward + coming back
In 1 cycle, he goes 2 steps = 2 m forward
In 1 cycle, he spends time of 8 units

So, in 4 cycles, displacement =8 m, time = 32 units
For 5th cycle, man reaches pit in 5 steps and falls in the pit
So, total time = 32+5=37 units

377025_419299_ans_798d3990722d44ae8d9c67d162fcc29c.png

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