Question

A drunkard walking in a narrow lane takes $5$ steps forward and $3$ steps backward, then again $5$ steps forward and $3$ steps backward, and so on. Each step is $1m$ long and requires $1s$. Determine how long the drunkard takes to fall in a pit $13m$ away from the starting point.

• A. $37s$
• B. $35s$
• C. $36s$
• D. $38s$

Answer 1

The correct option is A $37s$

In each process of going forward and coming backward, it will take $8s$, and he will move $2m$ in the $8s$. Time taken to cover first $8m$:

$\frac{8}{2}\times 8=32s$

Now after covering $8m$, when he takes five steps, he will fall into the pit. Time taken is $5s$.

Total time $=32+5=37s$

Final Answer: (𝑐)