Question

# A dye absorbs a photon of wavelength λ and re-emits the same energy into two photons of wavelength λ1 and λ2 respectively. The wavelength λ is related with λ1 and λ2 as:λ=(λ1+λ2)(λ1λ2)λ=(λ1λ2)(λ1+λ2)λ=(λ21+λ22)(λ1λ2)λ=(λ21λ22)(λ1+λ2)

Solution

## The correct option is B λ=(λ1λ2)(λ1+λ2) (E)incident=E1+E2  hc/λ=hc/λ1+hc/λ2 λ=(λ1λ2)(λ1+λ2)

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