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Question

A dye absorbs a photon of wavelength λ and re-emits the same energy into two photons of wavelength λ1 and λ2 respectively. The wavelength λ is related with λ1 and λ2 as:
  1. λ=(λ1+λ2)(λ1λ2)
  2. λ=(λ1λ2)(λ1+λ2)
  3. λ=(λ21+λ22)(λ1λ2)
  4. λ=(λ21λ22)(λ1+λ2)


Solution

The correct option is B λ=(λ1λ2)(λ1+λ2)
 (E)incident=E1+E2
 hc/λ=hc/λ1+hc/λ2
λ=(λ1λ2)(λ1+λ2)

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