The average force is=(20+10)2=15N
This means that the reading on the dynamometer lies between 10 and 15.
Let the reading on the dynamometer be xN.
Equating the two we have-
(20−x)6=(x−10)4
80−4x=6x−60
140=10x
x=14010
x=14N
The acceleration =(20−14)6=1
= 1m/s2