Question

$A+e^{-}\to A^{-}$
The given half cell reaction has a large negative reduction potential, it follows that:

• A. $A$ is readily reduced
• B. $A$ is readily oxidised
• C. $A^{-}$ is readily reduced
• D. $A^{-}$ is readily oxidised

Answer 1

The correct option is D $A^{-}$ is readily oxidised

As $A+e^{-}\to A^{-}$ has a large negative reduction potential, then the reduction of $A$ isn't feasible. The $A^{-}$ is readily oxidised to $A$.