Question

A earns Rs. 600 more than B. They both save together Rs. 3,200 which is one-fourth of A's salary plus one-sixth of B's salary. Find out their total monthly expenditure.(in Rs)

Answer 1

Let earning of A be Rs $x$ and of B be Rs $y$.

As per the given statements, " $=>x-y=600$ --- (1)

And, $\frac{x}{4}+\frac{y}{6}=3200=>3x+2y=38400$ --- (2)

Multiplying equation $\left(1\right)$ with $2$ we get, $2x-2y=1200$ ----- equation $\left(3\right)$

Adding equations $\left(2\right)$ and $\left(3\right)$, we get $5x=39600=>x=7920$

Substituting $x=7920$ in the equation $\left(1\right)$, we get $7920-y=600=>y=7320$

Hence, expenditure of A is $=$ Earning $-$ Saving $=x-\frac{x}{4}=\frac{3x}{4}=\frac{3\times 7920}{4}=Rs5940$

And expenditure of B is $=$ Earning $-$ Saving $=y-\frac{y}{6}=\frac{5y}{6}=\frac{5\times 7320}{6}=Rs6100$