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Question

(a) Electropositive nature of the element (s) increases down the group and decreases across the period.

(b) Electronegativity of the element decreases down the group and increases across the period.

(c) Atomix size increases down the group and decreases across a period (left to right).

(d) Metallic character increases down the group and decreases across the period.

On the basis of the above trends of the periodic table, answer the following about the elements with the atomic number 3 to 9.

(a) Name the most electropositive element among them.

(b) Name the most electronegative element.

(c) Name the element with the smallest atomic size.

(d) Name the element which is a metalloid.

(e) Name the element which shows maximum valency.

.


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Solution

Step 1:

Trends in periodic table:

The modern periodic table follows various trends based on their atomic radius, electronegativity, electropositive and electronegative nature, etc.

Step 2:

(a) Lithium with 3 as the atomic number is the most electropositive element because it loses an electron.
(b) Fluorine having 9 as the atomic number is the most electronegative element because it gains an electron
(c) Fluorine will have the smallest radius because of the higher nuclear charge.
(d) Boron is the metalloid.
(e) Carbon is the only element with maximum valency 4.


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