Question

A engine operating between ${150}^{\circ }C$ and ${25}^{\circ }C$ takes $500J$ heat from a higher temperature reservoir. If there are no frictional losses, then work done by engine is

• A. $147.7J$
• B. $157.75J$
• C. $165.85J$
• D. $169.95J$

Answer 1

Answer: (A)

$147.7J$

Given that,

$T_2=150+273=423K$

$T_1=25+273=298K$

$q=500J$

We know, $\frac{w}{q}=\frac{T_2-T_1}{T_2}$

By putting all those given values, we get

$w=147.7J$

So, the correct option is $A$