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Standard XII

Physics

Magnetic Moment

A equilateral...

Question

A equilateral triangular loop of side $l$ carries a current $I$ . It is placed in a magnetic field B such that the plane of the loop is in the direction of B. The torque on the loop is

Zero

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IBl

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\frac{\sqrt{3}}{2} I B^{2} l^{2}

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\frac{\sqrt{3}}{4} I B l^{2}

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Solution

The correct option is D $\frac{\sqrt{3}}{4} I B l^{2}$
$τ = N I A B = 1 \times I \times (\frac{\sqrt{3}}{4} l^{2}) B$
$= \frac{\sqrt{3}}{4} I B l^{2}$

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