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Question

a) Explain the shining of an air bubble in water.
b) A convex lens forms an image of the same size as the object at a distance of 30 cm from the lens. What is the distance of the object from the lens? What is the power of the lens? [5 MARKS]

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Solution

part a): 2 Marks
part b): 3 Marks

a) For water-air interface, the critical angle is 48.6
When light travelling in water, it is incident at an angle greater than 48.8, the light suffers total internal reflection. So the air bubble in water shines brilliantly

b) A convex lens forms the image of the same size as the object only when the object is placed at a distance 2f from the lens. In this case, the image is also equal to 2f from the lens.

Hence, 2f = 30 cm

or f = 15 cm = 0.15 m

Power of the lens, P = 1f = 10.15D = 6.6 D

The distance of the object from the lens is also 2f = 30 cm


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