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Question

A factor of a22ab+b2c2 is ___________.


A

ab

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B

abc

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C

a+b+c

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D

a+bc

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Solution

The correct option is B

abc


a22ab+b2c2=a2abab+b2c2=a(ab)b(ab) c2
=(ab)(ab) c2
=(ab)2 c2


Now, using the identity x2y2=(x+y)(xy) we get

(ab)2c2 = [(ab)+c][(ab)c]

Hence, the factors of (a22ab+b2c2) are (ab+c) and (abc)


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