A factory manufactures $120000$ pencils daily. The pencils are cylindrical in shape each of length $25$ cm and circumference of base as $1.5$ cm. Determine the cost of coloring the curved surfaces of the pencils manufactured in one day at Rs $0.05$ per $d m^{2} .$

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Solution

Circumference of circle $= 2 π r = 1.5$
Curved surface area of cylinder $= 2 π r h = 1.5 (25) = 37.5 c m^{2}$
$1$ dm $= 10$ cm
Curved surface $= 0.375 d m^{2}$
One day pencil area in $d m^{2} = 120000 (0.375) = 45000$
Cost of colouring $= 0.05 (45000) =$ Rs. $2250$

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A factory manufactures 120000 pencils daily. The pencils are cylindrical in shape each of length 25 cm and circumference of base as 1.5 cm. Determine the cost of coloring the curved surfaces of the pencils manufactured in one day at Rs 0.05 per dm2.

Circumference of circle =2πr=1.5Curved surface area of cylinder =2πrh=1.5(25)=37.5cm2 1 dm =10 cmCurved surface =0.375dm2One day pencil area in dm2=120000(0.375)=45000Cost of colouring =0.05(45000)= Rs.2250

A factory manufactures $120000$ pencils daily. The pencils are cylindrical in shape each of length $25$ cm and circumference of base as $1.5$ cm. Determine the cost of coloring the curved surfaces of the pencils manufactured in one day at Rs $0.05$ per $d m^{2} .$

Circumference of circle $= 2 π r = 1.5$
Curved surface area of cylinder $= 2 π r h = 1.5 (25) = 37.5 c m^{2}$
$1$ dm $= 10$ cm
Curved surface $= 0.375 d m^{2}$
One day pencil area in $d m^{2} = 120000 (0.375) = 45000$
Cost of colouring $= 0.05 (45000) =$ Rs. $2250$