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Question

A fair coin is tossed 100 times. The probability of getting tails an odd number of times is


  1. 12

  2. 14

  3. 18

  4. 38


Solution

The correct option is A

12


n=100,p=q=12p(x-an odd number)=p(x=1)+p(x=3)..............+p(x=99)=100c1+100c3..............+100c99210=12

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