A fair coin is tossed five times. If the outcomes are 2 heads and 3 tails (in some order), then what is the probability that the fourth toss is a head?
Total number of possible cases = 4 + 3 + 2 + 1 = 10
Favourable cases = {(H T T H T),(T H T H T ), (T T H H T ), (T T T H H)}
Total number of favourable cases = 4
∴ p(4th toss is a head)=4/10
=2/5