A fair coin is tossed n−times such that the probability of getting at least one head is at least 0.9. Then the minimum value of n is
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Solution
Probability of getting head in one time =12
Probability of getting head in n−time =(12)n
Probability of getting at least one head in n−time =1−(12)n
Now, 1−(12)n≥0.9 ⇒12n≤110 ⇒2n≥10 ∴n≥4