Question

A fair coin tossed 3 times .Find the probability of getting 2 heads and one tail.

Answer 1

Dear student,

The sample space obtained while three unbiased coins are tossed is given by {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}, where H means the head appears and T means the tail appears.

Thus, a total of 8 outcomes is obtained when three unbiased coins are tossed.

The outcomes of the event, getting 2 heads and 1 tail are HHT,HTH,THH

So required probability = $\frac{favourableoutcomes}{totaloutcomes}$ = $\frac{3}{8}$

Regards