Question

A fair dice is rolled twice. The probability that an odd number will follow an even number is

• A. $\frac{1}{2}$
• B. $\frac{1}{6}$
• C. $\frac{1}{3}$
• D. $\frac{1}{4}$

Answer 1

The correct option is D $\frac{1}{4}$

$P\left(oddnumber\right)=\frac{3}{6}=\frac{1}{2}$

$P\left(evennumber\right)=\frac{3}{6}=\frac{1}{2}$

Since both events are independent of each other as trials are independent,

So required probability = [P(even number)× P(odd number)]

$\therefore RequiredProbability=\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}$