A fair die is rolled and a number divisible by 3 shows up. The set of favourable outcomes when this event occurs is

{2, 3, 6}

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{3, 6}

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{3, 6, 9)

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Solution

The correct option is B ${3, 6}$
Clearly, only ${3, 6}$ are on the faces of a die and are divisible by 3.

Hence, $F a v o u r a b l e o u t c o m e s = {3, 6}$

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From the first 20 natural numbers, Ram selects a number at random. What is the number of favourable outcomes, if this number has to be divisible by 4?

A die is rolled and the outcomes are observed. Event A is an even number turns up and event B is a prime number turns up. Match the events on left with the outcomes on right.

$\begin{matrix} 1. Event A or B & P . {4, 6} 2. Event A and B & Q . {2} 3. Event A but not B & R . {2, 3, 4, 5, 6,} 4. Complementary event of B & S . {1, 4, 6} \end{matrix}$