A fair die is rolled. Find the probability of getting a number less than $5$ .

\frac{1}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{2}{3}$
In rolling a die, the sample space, $S = {1, 2, 3, 4, 5, 6}$
Therefore, $n (S) = 6$
Let $D$ be the event of getting number less than $5$ .
$D = {1, 2, 3, 4}$
Therefore, $n (D) = 4$
$P (D) =$ $\frac{n (D)}{n (S)} = \frac{4}{6} = \frac{2}{3}$

Suggest Corrections

Similar questions

6

5

500

Outcomes	$1$	$2$	$3$	$4$	$5$	$6$
Frequencies	$80$	$75$	$90$	$75$	$85$	$95$

2

200

1, 2, 3, 4, 5, 6

Outcome	$1$	$2$	$3$	$4$	$5$	$6$
Frequency	$40$	$38$	$43$	$29$	$28$	$22$

Find the probabilities of getting a number more than $1$ and less than $6$ in a toss (trial).

Join BYJU'S Learning Program