A fair die is rolled. Find the probability of getting a prime factor of $3$ .

\frac{1}{6}

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\frac{5}{6}

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\frac{1}{3}

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\frac{1}{2}

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Solution

The correct option is A $\frac{1}{6}$
In rolling a die, the sample space, $S = {1, 2, 3, 4, 5, 6}$
Therefore, $n (S) = 6$
Let $C$ be the event of getting a prime factor of $3$ .
$C = {3}$
Therefore, $n (C) = 1$
$P (C) =$ $\frac{n (C)}{n (S)} = \frac{1}{6}$

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