Question

A fair die is thrown two times. Find the chance that
Product of the numbers on the uppermost face is 12.

Answer 1

A fair die is thrown twice

$\Rightarrow$ Total possible outcomes$=36$

For the product of numbers, on the upper face to be $12$

Outcomes are $=\left\{\right(2,6),(3,4),(4,3),(6,2\left)\right\}$

$\Rightarrow$ Favourable outcomes$=4$

$\Rightarrow$ Probability $=\frac{4}{36}=\frac{1}{9}$

$\Rightarrow$ Chances of getting product$=12$ is $1$ in $9$.