A fair die is tossed repeatedly until a six is obtained. Let X denote the number of tosses required. The conditional probability that X≥6 is given X>3 equals
A
125216
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B
126181
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C
536
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D
2536
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Solution
The correct option is D2536 For X≥6, the probability is 5566+5567+...∞=5566(11−5/6)=(56)5 For X>3, 5364+5465+5566+...∞=(56)3 Hence, the conditional probability is (5/6)6(5/6)3=2536