A fair number cube has faces labeled and .
If the number cube is rolled times, about how many times should the result be a prime number?
Explanation for the correct option:
Step-1: Finding the probability of getting each number after rolling the cube
Given that the cube is fair and its faces are labeled as .
So, on rolling the cube, each of the six faces can be turned out with the equal probability . Now, the sum of the probabilities will be .
Hence, we must get:
Therefore, the probability of getting any one of the six numbers is .
Step-2: Finding the probability of obtaining a prime number
Out of six numbers , the primes are : i.e. there are four prime numbers.
Now, after rolling the cube, the result will be a prime number if any one of these four numbers turns up each with probability .
So, the probability of obtaining a prime numbers will be
Step-3: Calculating the number of times the result is a prime number:
Given that the number cube is rolled times.
Also, from Step-, we can see that the probability of getting a prime is .
Therefore, the number of times of getting a prime number out of times will be
Hence, option is the correct answer.