Question

A false balance has equal arms. An object weighs $\text{X}$ when placed in one pan and $\text{Y}$ when placed in other pan. Then the weight $\text{W}$ of the object is equal to

• A. $\frac{2}{\sqrt{X^2+Y^2}}$
  
• B. $\sqrt{XY}$
  
• C. $\frac{X+Y}{2}$
  
• D. $\frac{X^2+Y^2}{2}$
  

Answer 1

The correct option is C $\frac{X+Y}{2}$


As the balance has equal arms, the original weight of the object should be the mean weight of the two pans. When the false balance has equal arms then,
$W=\frac{X+Y}{2}$