Question

A family consumes $14kg$ kerosene in $30$ days. What is the average energy consumed per day, if the calorific value of kerosene is $48kJ{g}^{-1}$?

Answer 1

Step 1: Given data:

consumption of kerosene in $30$ days $=14kg$

$calorificvalue=48kJ{g}^{-1}$

Step 2: Find the consumption of kerosene in a day.

In $30$ days consumption of kerosene $=14kg=14000g$

In $1$day consumption of kerosene-

$$\begin{gathered} =\frac{14000}{30} \\ =\frac{1400}{3} \end{gathered}$$

Step 3: Find the average energy.

$$\begin{gathered} Averageenergy=consumptionin1day·calorificvalue \\ =\frac{1400}{3}g·48kJ{g}^{-1} \\ =1400\times 16 \\ =22400kJ \end{gathered}$$

Hence, the answer is $22400kJ$.