A family has 2 children. What is the probability that both are girls?

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Solution

Let g represents girl child and b represents boy child.

S = { (g, g), (b, g), (g, b), (b, b)} $\to$ n(S) = 4

Let E be the event that both are girls.

E = {(g, g)} $\to$ n(E) = 1

P(E) = n(E)/n(S) = $\frac{1}{4}$

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A family has 2 children. What is the probability that both are girls?

Let g represents girl child and b represents boy child. S = { (g, g), (b, g), (g, b), (b, b)} → n(S) = 4 Let E be the event that both are girls. E = {(g, g)} → n(E) = 1 P(E) = n(E)/n(S) = 14

Let g represents girl child and b represents boy child.

S = { (g, g), (b, g), (g, b), (b, b)} $\to$ n(S) = 4

Let E be the event that both are girls.

E = {(g, g)} $\to$ n(E) = 1

P(E) = n(E)/n(S) = $\frac{1}{4}$