A family of $4$ brothers and $3$ sisters is to be arranged in a row for a photograph. The number of ways in which they can seated if all the sisters are to sit together is:

120

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240

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360

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720

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Solution

The correct option is D $720$
$c o n s i d e r a l l s i s t e r s a s o n e b u n d l e, t h e n w e h a v e a t o t a l o f 5 e l e m e n t s, w h i c h c a n b e a r r a n g e d i n 5! w a y s = 120 w a y s a n d i n t h e s i s t e r s c a s e, t h r e e s i s t e r s, c a n b e a r r a n g e d i n 6 w a y s ∴ T o t a l p e r m u t a t i o n = 120 \times 6 = 720 w a y s$
So, the correct option is 720'.

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