Question

A family of six requires 30 kg of food per month. If six guests stayed over at their house for 10 days, how much extra food (in kg) would be required?

Answer 1

Six members of a family need 30 kg of food for a period of 30 days. If the number of members in the family increases, the amount of food required also increases.
Amount of food required by the family per day = $\frac{Quantityoffoodrequired}{Numberofdaysinamonth}=\frac{30}{30}$ = 1 kg.
Amount of food consumed by one family member in a day = $\frac{Amountrequiredbythefamilyperday}{Numberoffamilymembers}=\frac{1}{6}$ kg.

Amount of food required by 6 guests = $\frac{1}{6}\times$ 6 = 1 kg.
$\therefore$Amount of food required by 6 guests for 10 days = $1\times 10=10$ kg.