Question

A fan of 60 W runs for 75 hours in a month. How much electrical energy is consumed?

Answer 1

Given,

Power = $P=60W=\frac{60}{1000}=0.06KW$

Time = $t=75hrs$

We know that:

$\text{Electrical energy}=\text{power}\times \text{time}$ or, $E=Pt$

$\Rightarrow E=0.06\times 75=4.5KJ$.