A fan of power 550 W works for 3 hours- Calculate the energy consumed-A- 2 kW hB- 1-5 kW hC- 1-65 kW hD- 2-5 kW h

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Domestic Circuits

A fan of powe...

Question

A fan of power $550 W$ works for $3 h o u r s$ . Calculate the energy consumed.

$2 k W h$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$1.5 k W h$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$1.65 k W h$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$2.5 k W h$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$1.65 k W h$

Given:
Power = $550 W a t t$
Time for which the device is operated = $3 h o u r s$
Energy consumed (in $k W h$ ) = $\frac{P o w e r (W a t t) \times t i m e (h o u r)}{1000} = \frac{550 W a t t \times 3 h o u r s}{1000}$
$= \frac{1650}{1000} = 1.65 k W h$

Suggest Corrections

Similar questions

A fan of power $550 W$ works for $3 h o u r s$ . Calculate the energy consumed.

Five electric fans of 120 watts each are used for 4 hours. Calculate the electrical energy consumed in kilowatt hours.

A house hold use one heater of rated power 1000w for 1 hour a day, five bulbs of power 40w used for 5 hours a day and the fan of rated power 100w used for 10 hours a day. Find the number of units of electirical energy consumed in 10 days.

Q. A torch bulb is rated 5v and 500mA calculate it's 1.power 2.Resistance 3.Energy consumed when it is lighted for 6 hours everyday.

Join BYJU'S Learning Program

A fan of power 550 W works for 3 hours. Calculate the energy consumed.

The correct option is C 1.65 kWh Given: Power = 550 Watt Time for which the device is operated = 3 hours Energy consumed (in kWh) = Power(Watt)×time(hour)1000=550 Watt×3 hours1000 =16501000=1.65 kWh

A fan of power $550 W$ works for $3 h o u r s$ . Calculate the energy consumed.

The correct option is C
$1.65 k W h$

Given:
Power = $550 W a t t$
Time for which the device is operated = $3 h o u r s$
Energy consumed (in $k W h$ ) = $\frac{P o w e r (W a t t) \times t i m e (h o u r)}{1000} = \frac{550 W a t t \times 3 h o u r s}{1000}$
$= \frac{1650}{1000} = 1.65 k W h$