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Question

A farmer borrowed Rs.60,000 and agreed to repay with interest in a year in twelve monthly installments. The first installments was Rs.12,000. the next each installment was less than the preceding one by Rs.1000. Find the total amount he paid in the whole year and what was the interest charged?

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Solution

Total amount =Rs.60000
First installment (a)=Rs.12000
Common difference (d)=Rs.1000

Total no. of months in which amount to be paid (n)=12
Therefore,
Total amount paid by farmer
=n2[2a+(n1)d]=122[2×12000+(121)(1000)]=6×(2400011000)=6×13000=Rs.78000

Interest paid by farmer =7800060000=Rs.18000

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