A farmer borrows Rs. 1,000 and agrees to repay with a total interest of Rs. 140 in 12 installments, each installment being less than the preceding installment by Rs 10. What should be his first installment?
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Solution
Repay with a total 12 instalment = Rs. 140 ∴ Total of 12 instalment S12= Rs (1,000+140) = Rs. 1140 Number of instalments (n)=12 Let first instalments =a Difference (d)=−10 ∴Sn=n2[2a+(n−1)d] ∴S12=122[2a+11×(−10)] ⇒1140=6[2a−110] ⇒2a−110=190 ⇒2a=300 a=150 ∴ First instalment is Rs. 150.