A farmer buys a used tractor for Rs. 12000. He pays Rs. 6000 cash and agrees to pay the balance in annual instalments of Rs. 500 plus 12% interest on the unpaid amount. How much will the tractor cost him ?
Total cost of the tractor = Rs. 12000
Cash amount paid = Rs. 6000
Balance amount = Rs. 12000 - Rs. 6000 = Rs. 6000
Interest of 1st instalment
=Rs.6000×12×1100=Rs. 720
Amount of second instalment
=Rs.5500×12×1100=Rs. 660
Amount of second instalment
= Rs. 500 + Rs. 600 = Rs. 1160
Interest of the 3rd instalment
=5000×12×1100=Rs. 600
Amount of third instalment
= 500 + 600 = Rs. 1100
The sequence of instalment is
1220, 1160, 1100 ....
Here a = 1220 d = 1160 - 1220 = -60 and n = 12
∴ Sn=n2[2a+(n−1)d]
∴ S12=122[2×1220+(12−1)×−60]
=6[2440−660]=Rs. 10680