The correct option is
A Rs.16680Given, the farmer pays a tractor of Rs.12000.
He pays Rs.6000 in cash.
Therefore, unpaid amount=Rs.12000−Rs.6000=Rs.6000
The interest to be paid annually is 12% of 6000, 12% of 5500, 12% of 5000,...., 12% of 500.
Thus, total interest to be paid= 12% of 6000+12% of 5500+12% of 5000+.....+12% of 500
=12% of(6000+5500+5000+.....+500)
=12% of(500+1000+1500+....+6000)
Since, the series is an A.P. with both the first term and common difference equal to 500.
Let, the number of terms of the A.P. is n
∴6000=500+(n−1)500⇒1+(n−1)=12⇒n=12
∴ Sum of the A.P.
=122[2(500)+(12−1)500]=6[1000+5500]=6[6500]=39000
Thus, total interest to be paid=12% of(500+1000+1500+...+6000)
=12% of 39000
=Rs.4680
∴ Tractor cost for the farmer=(Rs.12000+Rs.4680)=Rs.16680.