A farmer connects a pipe of internal diameter 20 cm from a canal into a cylindrical tank in her field, which is 10 m in diameter and 2 m deep. If, water flows through the pipe at the rate of 3 km/h, in how much time will the tank be filled(in minutes)?
100
Given that diameter of pipe, d = 20 cm
Then, radius of pipe,
r=202=10 cm=0.1 m
Speed of water flowing through pipe = 3 km/h = 3000 m/h
Pipe is in the form of a cylinder.
So, volume of water flowing through pipe in 1 hour
=πr2h=π×0.1×0.1×3000=30π m3
Let the cylindrical tank be filled in x hours.
Then, volume of water flowing through pipe in x hours
=30xπ m3
Also it is given that,
diameter of cylindrical tank, d1=10 m
⇒ radius of cylindrical tank, r1=102=5 m
Height of cylindrical tank, h1=2 m
Volume of cylindrical tank
=π(r1)2h1=π×5×5×2=50π m3
Now, volume of water flowing through pipe in x hours = volume of cylindrical tank
⇒30xπ=50π
⇒x=5030=53 hours
i.e., x=5×603 minutes =100 minutes
∴ The tank will be filled in 100 minutes.