A farmer crossed a walnut combed chicken with a single combed one and obtained all walnut combed chickens in F $_{1}$ . The genotype of the parents is

RrPp x rrpp

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RRPP x rrpp

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RRpp x rrpp

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RRPp x rrpp

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Solution

The correct option is B RRPP x rrpp
$R P$ $R P$ $R P$ $R P$
$r p$ $R P$ $r p$ $R P$ $r p$ $R P$ $r p$ $R P$ $r p$
$r p$ $R P$ $r p$ $R P$ $r p$ $R P$ $r p$ $R P$ $r p$
$r p$ $R P$ $r p$ $R P$ $r p$ $R P$ $r p$ $R P$ $r p$
$r p$ $R P$ $r p$ $R P$ $r p$ $R P$ $r p$ $R P$ $r p$
The Punnet square gives the offsprings obtained in the $F_{2}$ generation. $R$ or $r$ stands for gene for walnut comb and $P$ or $p$ stands for gene for single comb, An interaction between $R P$ and $r p$ results in all walnut combed chickens. Thus, the correct answer is option B.

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