Question

A farmer divides his herd of $n$ cows among his four sons so that one son gets one-half the herd, a second son, one-fourth, a third son, one-fifth, and the fourth son, $7$ cows. Then $n$ is:

• A. $80$
• B. $100$
• C. $140$
• D. $180$
• E. $240$

Answer 1

Answer: (C)

$140$

$n=\frac{1}{2}n+\frac{1}{4}n+\frac{1}{5}n+7;n=140$