A farmer divides his herd of x cows among his four sons such that first son gets one-half of the herd, the scond son gets one-fourth, and the third son gets one fifth and the fourth son gets 7 cows, then the value of x is :
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Solution
1st son will get x/2 2nd will get x/4 third will get x/5 and 4th will get 7.
Sum of all cows = x
So, x/2 + x/4 + x/5 +7 = x
(10x+ 5x+ 4x+ 140) /20 = x or, 19x + 140 = 20x or, x = 140