Question

A farmer sold $2$ bullocks for $Rs24000$ each. On one bullock he gained $25\%$ and on the other, he lost $20\%$. Find his total profit or loss percent

Answer 1

Given S.P of each Bullock $=$ Rs 24000

(i) $Profit$ $=$$S.P-C.P$

$\Rightarrow$25% of C.P $=$ S.P - C.P

$\Rightarrow$$\frac{25}{100}$C.P$=$24000 - C.P

$\Rightarrow$$\frac{1}{4}$C.P + C.P$=$ 24000

$\Rightarrow$$\frac{5}{4}$C.P $=$ 24000

$\Rightarrow$C.P $=$ Rs 19200

(ii)$Loss$ $=$ $C.P-S.P$

$\Rightarrow$ 20% of C.P $=$ C.P - S.P

$\Rightarrow$$\frac{20}{100}$ C.P $=$ C.P - 24000

.$\Rightarrow$ C.P - $\frac{1}{5}$ C.P $=$ 24000

$\Rightarrow$$\frac{4}{5}$ C.P $=$ 24000

$\Rightarrow$C.P $=$ 6000$\times$5

$\Rightarrow$ C.P $=$ Rs 30000

Now Total S.P of 2 Bullocks $=$ Rs 48000

Total C.P of 2 Bullocks $=$ Rs 19200 +Rs30000

$=$ Rs 49200

Profit $=$ $S.P-C.P$

$=$ Rs 48200 - 48000

$=$ Rs 1200

Profit % $=$ $\frac{P}{C.P}\times 100$

$=$ $\frac{1200}{49200}\times 100$

$=2.44$