A farmer wishes to start a 100 sq. m. rectangular vegetable garden. Since he has only 30 m barbed wire, he fences three sides of the garden letting his house compound wall act as the fourth side fencing. The dimension of the garden is:
20 m × 5 m
We have: 2b + l = 30 ⇒ l = 30 - 2b
Area = 100 m2 ⇒ l × b = 100 ⇒ b (30 -- 2b) = 100 ⇒ b2 -- 15b + 50 = 0
⇒ (b -- 10) (b -- 5) = 0 ⇒ b = 10 or b = 5
When b = 10, l = 10 and when b = 5, l = 20.
Since the garden is rectangular, so its dimension is 20 m × 5 m.