Question

A fast blowing town has now $30,000$ cattle, during the last few years, the number of cattle depreciates at the rate of $20$%.If depreciation continues at this rate what will be the cattle population after $3$ years?

Answer 1

$P=30,000$

$r=-20\%$

$n=3years$ $[A=P{(1+\frac{r}{100})}^n]$

$A_1=30,000{(1-\frac{20}{100})}^3$

$=30,000\times \frac{80}{100}\times \frac{80}{100}\frac{80}{100}$

$=15,360$ is present cattle population