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Question

A fast moving neutron collides with a Lithium atom at rest in ground state with kinetic energy K. List - 1 gives different values of K and List- 2 gives various possible phenomena

List-1List-2IK=81.6 eVPElastic collision may take placeIIK=104.9 eVQElastic collision will take placeIIIK=108.8 eVRInelastic collision may take placeIVK=200 eVSPerfectly inelastic collision may take placeTAtom may get ionisedUPhoton may be emitted

Match entries in List - 1 with those in List - 2.

A
I P,S,U; II P,R,U; III P,R,S,T; IV P,R,U,T;
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B
I Q II P,S,U; III P,R,S,U; IV P,R,T,U;
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C
I Q; II P,R,S; III P,R,T,U; IV P,R,T,U
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D
I P,R; II P,R,U; III R,S,T,U; IV P,R,T,U;
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Solution

The correct option is B I Q II P,S,U; III P,R,S,U; IV P,R,T,U;
K.E for perfectly inelastic (head on) collision

m1V0=(m1+m2)V [By COM] ...... (1)

12m1V20=12(m1+m2)v2+Q [By COE] ...... (2)

By (1) and (2) K=Q(1+m1m2) here K=12m1V20
and Q is energy of photon emitted in various transition.

For Li,
Q=13.6×32(11n2) n = 1, 2, 3, ....
Q=122.4(11n2)Q1=91.8,Q2=108.8,Q3=114.75
Qmax=122.4

Also, K=Q(1+m1m2)=Q(1+17)=Q87

Kmin=Q1×87=104.9eV
Kmax=Qmax×87=122.4×87=139.8eV

Question I:
K=81.6
K<Kmin. So only elastic collision is possible.

Question II:
K=104.9
K=Kmin. So perfectly inelastic collision can happen, and electron can get excited. If electron is not excited then elastic collision will happen.

Question III:
K=108.8
So, perfectly inelastic collision can happen by exciting the electron to 2nd level. Or, inelastic collision can happen by exciting the electron to the 1st level.

Question IV:
K=200>Kmax
Inelastic collision can happen exciting the electron. K>Kmax so, the atom can get ionised.


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