A fast train takes one hour less than a show train for a journey of $200 k m$ . If the speed of the slow train is $10 k m / h r$ less than that of the fast train, find the speed of two trains.

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Solution

Ans : 50 km/hr, 40 km/hr
Hint :
Let the speed of the fast train be x km/hr. Then, speed of slow train = (x - 10) km/hr. Since, fast
$∴ \frac{200}{(x - 10)} - \frac{200}{x} = 1$

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A fast train takes one hour less than a show train for a journey of 200 km. If the speed of the slow train is 10km/hr less than that of the fast train, find the speed of two trains.

Ans : 50 km/hr, 40 km/hrHint :Let the speed of the fast train be x km/hr. Then, speed of slow train = (x - 10) km/hr. Since, fast ∴200(x−10)−200x=1

A fast train takes one hour less than a show train for a journey of $200 k m$ . If the speed of the slow train is $10 k m / h r$ less than that of the fast train, find the speed of two trains.

Ans : 50 km/hr, 40 km/hr
Hint :
Let the speed of the fast train be x km/hr. Then, speed of slow train = (x - 10) km/hr. Since, fast
$∴ \frac{200}{(x - 10)} - \frac{200}{x} = 1$