A father divides a sum of ₹ 20,000 in two funds in the name of his two sons aged 10 years and 30 years in such a way that both receive the same amount of interest at the age of 40 years.
The rate of interest offered in both the funds are same.
Find the amount invested for his younger son.

₹ 15,000

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₹ 5,000

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₹ 10,000

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₹ 25,000

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Solution

The correct option is A ₹ 15,000
Let the sum invested for the elder son be ₹ x.
Hence, the sum invested for the younger son = ₹ (20,000-x).

The Simple Interest earned on a sum of ₹ P for a period of T years at the rate of R % p.a S.I is given by $\frac{P \times R \times T}{100}$ .

Since, both of them receive the same interest at the age of 40 years,

$\frac{x \times R \times 10}{100}$ = $\frac{(20, 000 - x) \times R \times 30}{100}$

$\Rightarrow x = ₹ 15, 000$

Hence, the amount invested for his younger son = ₹ (20,000-x) = ₹ (20,000-15,000) = ₹ 5,000.

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A father divides a sum of ₹ 20,000 in two funds in the name of his two sons aged 10 years and 30 years in such a way that both receive the same amount of interest at the age of 40 years. The rate of interest offered in both the funds are same. Find the amount invested for his younger son.

A father divides a sum of ₹ 20,000 in two funds in the name of his two sons aged 10 years and 30 years in such a way that both receive the same amount of interest at the age of 40 years.
The rate of interest offered in both the funds are same.
Find the amount invested for his younger son.