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Question
A father is 3 times as old as his son. In 12 years time, he will be twice as old as his son. Find their present ages.?
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Solution
Solution:
Let x be the current age of the son.
Son = x, Father = 3x
In 12 years
Son = x + 12, Father = 3(x+12) “OR” 3x + 12
Given ,after 12 years
2* Age of son = Age of father
2(x + 12) = 3x + 12
2x + 24 = 3x + 12
24 - 12 = x
Therefore, current(present) age of son is 12, and father is 36
Solution:
Let x be the current age of the son.
Son = x, Father = 3x
In 12 years
Son = x + 12, Father = 3(x+12) “OR” 3x + 12
Given ,after 12 years
2* Age of son = Age of father
2(x + 12) = 3x + 12
2x + 24 = 3x + 12
24 - 12 = x
Therefore, current(present) age of son is 12, and father is 36
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