A father is six times as old as his son. After $4$ years he will be only four times as old as his son will be. What are their present ages?

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Solution

Let the age of son be $x$
So, father's age be $6 x$
second condition
$= 4 (x + 4) = 6 x + 4$
$x = 6$ year
hence,
son's age is $6$ year
father's age is $36$ year

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A father is six times as old as his son. After 4 years he will be only four times as old as his son will be. What are their present ages?

Let the age of son be xSo, father's age be 6xsecond condition=4(x+4)=6x+4x=6 yearhence,son's age is 6 yearfather's age is 36 year

A father is six times as old as his son. After $4$ years he will be only four times as old as his son will be. What are their present ages?

Let the age of son be $x$
So, father's age be $6 x$
second condition
$= 4 (x + 4) = 6 x + 4$
$x = 6$ year
hence,
son's age is $6$ year
father's age is $36$ year