Question

A father is three times as old as his son. In $12$ years time, he will be twice as old as his son. Find the present ages of father and the son.

Answer 1

Let the present age of son be $x$.

And the present age of father be $3x$.

As given in the question,

The age of son after $12$ years = $x+12$

And the age of the father after $12$ years = $2\left(x+12\right)$

Therefore,

$\begin{array}{rcl}3x+12& =& 2(x+12)\\ & =& 3x+12=2x+24\\ & =& x=12\end{array}$

Therefore,

The present age of the son is $12$ years.

The present age of the father is $12\times 3=36$ years.